ECZ 2014 · O-Level Paper 1 — Algebra
Solve the simultaneous equations 3x = 4y + 1, 7x + y = 23.
- A. x = 4, y = −5
- B. x = 2, y = 3
- C. x = 3, y = −2
- D. x = 3, y = 2
Verified working — step 1
From the second equation y = 23 − 7x. Substituting: 3x = 4(23 − 7x) + 1 = 93 − 28x, so 31x = 93 and x = 3. Then y = 23 − 21 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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