ECZ 2014 · O-Level Paper 1 — Circle Theorems
In the diagram, O is the centre of the circle ABCD. AC is a diameter, AD and BC are produced to meet at E, angle CED = 27° and angle ACB = 43°. Find angle CAD.
- A. 27°
- B. 16°
- C. 47°
- D. 63°
Verified working — step 1
AC is a diameter, so angle ABC = 90° and in triangle ABC angle BAC = 180° − 90° − 43° = 47°. Since BCE is a straight line, angle ABE = 90°, so in triangle ABE angle BAE = 180° − 90° − 27° = 63°. As D lies on AE, angle CAD = angle BAE − angle BAC = 63° − 47° = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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