ECZ 2014 · O-Level Paper 1 — Circle Theorems
In the diagram, O is the centre of the circle ABCD. AC is a diameter, AD and BC are produced to meet at E, angle CED = 27° and angle ACB = 43°. Find angle DCE.
- A. 90°
- B. 27°
- C. 117°
- D. 63°
Verified working — step 1
AC is a diameter, so angle ADC = 90°. ADE is a straight line, so angle CDE = 180° − 90° = 90°. In triangle CDE, angle DCE = 180° − 90° − 27° = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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