ECZ 2011 · O-Level Paper 1 — Bearings
In the diagram, C is due south of A, AB = BC and the bearing of B from A is 110°. Find the bearing of C from B.

- A. 290°
- B. 250°
- C. 070°
- D. 200°
Verified working — step 1
AC points due south, so angle CAB = 180 - 110 = 70°. AB = BC makes the triangle isosceles, so angle BCA = 70° and angle ABC = 40°. The bearing of A from B is 110 + 180 = 290°, and C sits 40° round from A, giving 290 - 40 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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