ECZ 2011 · O-Level Paper 1 — Circle Theorems
In the diagram, ABC is a straight line and BS is parallel to UT. Angle SBV = 64° and BS bisects angle ABV. Find angle ABS.
- A. 32°
- B. 116°
- C. 128°
- D. 64°
Verified working — step 1
BS bisects angle ABV, so it splits that angle into two equal parts. One of them is angle SBV = 64°, so angle ABS = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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