ECZ 2010 · O-Level Paper 1 — Circle Theorems

In the diagram, BD = 9 cm and DT = 3 cm, with ECT a tangent at C. Calculate the length of CT.

Diagram for ECZ 2010 · O-Level Paper 1
  • A. 3 cm
  • B. 9 cm
  • C. 12 cm
  • D. 6 cm

Verified working — step 1

BD passes through the centre, so BDT is a secant with TD = 3 and TB = 3 + 9 = 12. By the tangent-secant rule, CT2 = TD x TB = 3 x 12 = 36, so CT = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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