ECZ 2010 · O-Level Paper 1 — Circle Theorems
In the diagram, PQR is parallel to STV, angle SQT = 90°, angle QST = 42° and PQ = QT. Calculate angle TQR.
- A. 42°
- B. 48°
- C. 90°
- D. 132°
Verified working — step 1
In triangle SQT the angles sum to 180, so angle QTS = 180 - 90 - 42 = 48°. PQR is parallel to STV with QT as transversal, so angle TQR = angle QTS = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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