ECZ 2017 · O-Level Paper 1 — Index Notation

Evaluate (8116)−1/4 + (8116)0.

  • A.
  • B. 1⅔
  • C.
  • D.

Verified working — step 1

(8116)14 = 32, so the negative index inverts it to 23. Any non-zero value to the power 0 is 1, giving 23+ 1 = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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