ECZ 2016 · O-Level Paper 1 — Earth Geometry
What is the shortest distance over the Earth’s surface between A(32°N, 8°W) and B(40°N, 172°E)? [R = 6370 km, π = 22⁄7]
- A. 6 006 km
- B. 16 016 km
- C. 12 012 km
- D. 5 720 km
Verified working — step 1
8°W and 172°E differ by 180°, so A and B lie on one great circle through the poles. Over the North Pole the angle = (90 − 32) + (90 − 40) = 108°. Distance = 108⁄360 × 2 × 22⁄7 × 6370 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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