ECZ 2016 · O-Level Paper 1 — Circle Theorems
For the same circle (tangent at P meets QS produced at T, ∠PQS = 26°, ∠QPR = 42°), calculate PTQ.
- A. 32°
- B. 26°
- C. 42°
- D. 22°
Verified working — step 1
The tangent at P is perpendicular to diameter PR, so ∠TPQ = 90° + 42° = 132°. With ∠PQT = 26°, triangle PTQ gives ∠PTQ = 180° − 132° − 26° = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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