ECZ 2018 · GCE Paper 1 — Sequences and Series

The first three terms of an arithmetic progression are 5, 7 and 9. Find the sum of the first 12 terms.

  • A. 192
  • B. 27
  • C. 384
  • D. 96

Verified working — step 1

Use Sₙ = n2[2a + (n − 1)d] with a = 5, d = 2, n = 12: S₁₂ = 6[10 + 11 × 2] = 6 × 32 = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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