ECZ 2018 · GCE Paper 1 — Matrices
The transpose of a matrix P is 134251301. Write down the matrix P.
- A. [1 2 3; 3 5 0; 4 1 1]
- B. [1 3 4; 2 5 1; 3 0 1]
- C. [3 0 1; 2 5 1; 1 3 4]
- D. [4 3 1; 1 5 2; 1 0 3]
Verified working — step 1
Transposing twice brings a matrix back: (PT)T = P. So transpose the GIVEN matrix once more.The full step-by-step working and final answer, plus the video lesson for this topic, are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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