ECZ 2019 · GCE Paper 1 — Matrices

Given that R = [2 −1; 1 3] and S = [1 0 −4; −2 1 1] (rows separated by semicolons), find RS.

  • A. [2 0 4; −2 3 3]
  • B. [4 1 −9; −5 3 −1]
  • C. [0 −1 −9; 7 3 −1]
  • D. [4 −1 −9; −5 3 −1]

Verified working — step 1

Each row of R multiplies each column of S. Row 1: (2)(1)+(−1)(−2) = 4; (2)(0)+(−1)(1) = −1; (2)(−4)+(−1)(1) = −9. Row 2: (1)(1)+(3)(−2) = −5; (1)(0)+(3)(1) = 3; (1)(−4)+(3)(1) = −1. So RS = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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