ECZ 2019 · GCE Paper 1 — Bearings
Mr Moenda travels on a bearing of 141° from A to B. He then continues from B on a bearing of 255° to C. The angle BCA = 35°. Find the bearing of A from B.
- A. 141°
- B. 321°
- C. 219°
- D. 039°
Verified working — step 1
The bearing of A from B is the reverse of the bearing of B from A. Since 141° < 180°, add 180°: 141° + 180° = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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