ECZ 2019 · GCE Paper 1 — Bearings
Mr Moenda travels on a bearing of 141° from A to B, then from B on a bearing of 255° to C. The angle BCA = 35°. Find the bearing of A from C.
- A. 010°
- B. 075°
- C. 110°
- D. 040°
Verified working — step 1
The bearing of B from C is the back bearing of 255°: 255° − 180° = 075°. At C, the angle between CB and CA is 35°, and A lies anticlockwise (north side) of the line CB, so the bearing of A from C = 075° − 35° = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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