ECZ 2017 · GCE Paper 1 — Introduction To Calculus
Find the derivative of y = 2x³ − 2x² − 3x + 1, with respect to x.
- A. 6x² − 4x − 3
- B. 6x³ − 4x² − 3x
- C. x⁴/2 − 2x³/3 − 3x²/2 + x
- D. 6x² − 2x − 3
Verified working — step 1
Differentiate term by term (multiply by the power, drop the power by one): 2x³ → 6x², −2x² → −4x, −3x → −3, and the constant 1 → 0. So dydx= …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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