ECZ 2017 · GCE Paper 1 — Approximations
A bag of potatoes has mass (15.4 ± 0.05) kg. Find the tolerance of this mass.
- A. 0.05 kg
- B. 0.1 kg
- C. 0.5 kg
- D. 0.025 kg
Verified working — step 1
Tolerance is the full width between the limits: (15.4 + 0.05) − (15.4 − 0.05) = 15.45 − 15.35 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
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