ECZ 2024 · GCE Paper 2 · Question 6 — Sequences and Series
Question from ECZ 2024 · GCE Paper 2 · Question 6
(a) The first three terms of a geometric progression are 3w - 2, 3w + 6 and 3w + 30. Find the
(a(i)) value of w,[3]
Verified working — step 1
Consecutive GP terms share a ratio, so (2nd)2 = (1st)(3rd):(a(ii)) nth term,[2]
Verified working — step 1
With w = 2 the terms are 4, 12, 36, ... so a = 4 and r = 124 = …(a(iii)) sum of the first 4 terms.[2]
Verified working — step 1
Sn = arn - 1r - 1 with a = 4, r = 3:(b) Simplify 10am2 n2 ÷ 5a32m2 n2.[2]
Verified working — step 1
Multiply by the reciprocal:The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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