ECZ 2024 · GCE Paper 2 · Question 9 — Trigonometry
The diagram shows a triangle PQR in which PR = 8.9cm, QR = 12.5cm and angle PRQ = 130.6°.
(a(i)) Calculate PQ.[5]
Verified working — step 1
Use the Cosine Rule:(a(ii)) Calculate the area of triangle PQR.[2]
Verified working — step 1
Area = 12× PR × QR × sin(PRQ)(a(iii)) Calculate the shortest distance from R to PQ.[2]
Verified working — step 1
Using Area = 12× base × height, with base PQ:(b) Solve the equation 2 sin x = 1 for 90° ≤ x ≤ 270°.[1]
Verified working — step 1
2 sin x = 1(c) Simplify 3x^3 - 6x^2x^2 - 2x.[2]
Verified working — step 1
3x^3 - 6x^2x^2 - 2xThe full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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