ECZ 2024 · GCE Paper 2 · Question 9 — Trigonometry
Question from ECZ 2024 · GCE Paper 2 · Question 9
(a) The diagram shows a triangle PQR in which PR = 8.9 cm, QR = 12.5 cm and angle PRQ = 130.6°. Calculate
(a(i)) PQ,[5]
Verified working — step 1
Two sides and the included angle: cosine rule.(a(ii)) the area of triangle PQR,[2]
Verified working — step 1
Two sides and the included angle: Area = (12)(PR)(QR) sin(PRQ)(a(iii)) the shortest distance from R to PQ.[2]
Verified working — step 1
The shortest distance is the perpendicular height h from R onto PQ.(b) Solve the equation 2 sin x = 1 for 90° ≤ x ≤ 270°.[1]
Verified working — step 1
sin x = 12, with related acute angle 30°.(c) Simplify 3x3 - 6x2x2 - 2x.[2]
Verified working — step 1
Factor top and bottom fully:The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
Have a different question?
Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.
Search any past-paper question