ECZ 2025 · GCE Paper 2 · Question 6 — Vectors In Two Dimensions

In the diagram, AD = 3a, AB = 2b, AB : BC = 1 : 2, BX : BD = 1 : 4 and E is the midpoint of CD. A flowchart is given (see diagram): Start; Enter R, h, r; Is r > R? Yes: Print 'error, r is not valid'; No: V = π*h3*(R2 + r2 + R*r); Print V; Stop.

Diagram for ECZ 2025 · GCE Paper 2 · Question 6

(a(i)) Express BD in terms of a andorb.[1]

Verified working — step 1

BD = AD - AB = …

(a(ii)) Express DX in terms of a andorb.[1]

Verified working — step 1

Since AB:BC = 1:2, BC = 2·AB = 4b (same direction as AB).

(a(iii)) Express CD in terms of a andorb.[1]

Verified working — step 1

AC = AB + BC = 2b + 4b = 6b (from part ii, BC = …

(a(iv)) Express AE in terms of a andorb.[2]

Verified working — step 1

DC = -CD = -3a + 6b.

(b) Write a pseudocode corresponding to the flowchart program above.[5]

Diagram for part (b)

Verified working — step 1

Start

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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