ECZ 2016 · O-Level Paper 2 · Question 6 — Introduction To Calculus

The equation of a curve is y = x3 - (32)x2.

(a) The equation of a curve is y = x3 - (32)x2. Find the equation of the normal where x = 2.[3]

Verified working — step 1

At x = 2: y = 23 - (32)(22) = 8 - 6 = 2, so the point is (2, 2).

(b) Find the coordinates of the stationary points.[3]

Verified working — step 1

dydx= 3x2 - 3x = 3x(x - 1) = 0, so x = 0 or x = 1.

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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