ECZ 2017 · GCE Paper 2 · Question 2 — Sequences and Series

Question from ECZ 2017 · GCE Paper 2 · Question 2

(a) Simplify m2 - 1m2 - m.[2]

Verified working — step 1

Factorise top and bottom.

(b) The first three terms of a geometric progression are 6 + n, 10 + n and 15 + n. Find

(b(i)) the value of n,[2]

Verified working — step 1

In a GP consecutive ratios are equal: 10 + n6 + n = 15 + n10 + n.

(b(ii)) the common ratio,[2]

Verified working — step 1

Substitute n = 10: the terms become 16, 20 and 25.

(b(iii)) the sum of the first 6 terms of this sequence.[3]

Verified working — step 1

Sn = arn - 1r - 1 with a = 16, r = 54, n = 6.

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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