ECZ 2017 · GCE Paper 2 · Question 10 — Trigonometry
In triangle PQR, QR = 36.5m, angle PQR = 36° and angle QPR = 46°.
(a(i)) Calculate PQ.[4]
Verified working — step 1
Angle R = 180° - 36° - 46° = 98°.(a(ii)) Calculate the area of triangle PQR.[2]
Verified working — step 1
Area = 12× PQ × QR × sin Q(a(iii)) Calculate the shortest distance from R to PQ.[2]
Verified working — step 1
Let h = shortest distance from R to PQ.(b) Solve the equation sin θ = 0.6792 for 0° ≤ θ ≤ 360°.[2]
Verified working — step 1
sin θ = 0.6792(c) Simplify (p2 q3 / 4) × (8pq) ÷ 2p2 q.[2]
Verified working — step 1
(p²q³/4) × (8pq) ÷ (2p²q)The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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