ECZ 2023 · O-Level Paper 2 · Question 11 — Trigonometry
In the triangle PQR, PQ = 41.6 m, PR = 70 m and angle PQR = 105 degrees.
(a(i)) In the triangle PQR, PQ = 41.6 m, PR = 70 m and angle PQR = 105 degrees. Calculate angle QPR.[5]
Verified working — step 1
By the sine rule, sin RPQ= sin QPR:(a(ii)) Calculate the area of triangle PQR.[2]
Verified working — step 1
PQ and PR both meet at P, so use the angle between them:(a(iii)) Calculate the shortest distance from Q to PR.[2]
Verified working — step 1
The shortest distance is the perpendicular height h from Q to PR.(b) Solve the equation tan(theta) = 2.75 for 180 <= theta <= 270 degrees.[1]
Verified working — step 1
The acute angle with tangent 2.75 is 70.0 degrees.(c) Simplify 3d^2 - 27d + 3.[2]
Verified working — step 1
3d2 - 27 = 3(d2 - 9) = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
Have a different question?
Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.
Search any past-paper question