ECZ 2024 · O-Level Paper 2 · Question 4 — Matrices
Question from ECZ 2024 · O-Level Paper 2 · Question 4
(a) Given that matrix P = 3-1-42, find its
(a(i)) determinant,[2]
Verified working — step 1
The determinant of matri…(a(ii)) inverse.[2]
Verified working — step 1
For abcd the inverse is (1det) d-b-ca.(b) Given the geometric progression 10, 30, 90, ..., find the
(b(i)) 10th term,[2]
Verified working — step 1
a = 10 and r = 3010 = 3.(b(ii)) sum of the first 6 terms,[3]
Verified working — step 1
For r > 1: Sn = arn - 1r - 1(b(iii)) geometric mean of 2 430 and 21 870.[2]
Verified working — step 1
The geometric mean of two numbers is the square root of their product.The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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