ECZ 2018 · GCE Paper 2 · Question 1 — Matrices
Matrix A = 2x23x.
(a(i)) Find the positive value of x for which the determinant of A is 12.[2]
Verified working — step 1
det(A) = (2x)(x) - (2)(3) = 2x2 - 6(a(ii)) Hence or otherwise, write A-1.[2]
Verified working — step 1
With x = 3, A = 6233, det(A) = 12(b) Solve the equation x2 - 4x - 2 = 0, giving your answers correct to 2 decimal places.[5]
Verified working — step 1
x2 - 4x - 2 = 0The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
Have a different question?
Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.
Search any past-paper question