ECZ 2018 · GCE Paper 2 · Question 2 — Sequences and Series
Question from ECZ 2018 · GCE Paper 2 · Question 2
(a) Simplify 7st315u3v2 × 5u3v28s3t2.[2]
Verified working — step 1
Multiply the fractions and gather powers.(b) In a geometric progression, the third term is 29 and the fourth term is 227. Find
(b(i)) the first term and the common ratio,[3]
Verified working — step 1
Let the first term be a and the common ratio r.(b(ii)) the sum of the first 5 terms of the geometric progression,[2]
Verified working — step 1
Since r < 1, Sn = a1 - rn1 - r.(b(iii)) the sum to infinity.[2]
Verified working — step 1
Since |r| < 1, the sum to infinity is a1 - r.The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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