ECZ 2018 · GCE Paper 2 · Question 2 — Sequences and Series
In a geometric progression, the third term is 29and the fourth term is 227.
(a) Simplify (7st3 / 15u3v2) × (5u3v28s3t2).[2]
Verified working — step 1
Multiply the fractions and simplify powers:(b(i)) Find the first term and the common ratio.[3]
Verified working — step 1
Let first term = a, common ratio = r.(b(ii)) Find the sum of the first 5 terms of the geometric progression.[2]
Verified working — step 1
Use Sn = a1-r^n1-rfor r<1, n=5:(b(iii)) Find the sum to infinity.[2]
Verified working — step 1
Since |r|<1, use S∞ = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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