ECZ 2014 · O-Level Paper 2 · Question 2 — Matrices

Question from ECZ 2014 · O-Level Paper 2 · Question 2

(a) Given that A = 5210 and B = -100-1, find

(a(i)) the inverse of matrix A,[2]

Verified working — step 1

A = 5210, so det A = (5)(0) - (2)(1) = -2.

(a(ii)) 3A - B,[2]

Verified working — step 1

3A multiplies every entry of A by 3: 15630.

(a(iii)) AB.[2]

Verified working — step 1

Multiply row into column.

(b) Express 52y - 1 - 63y - 1 as a single fraction in its simplest form.[3]

Verified working — step 1

Common denominator (2y - 1)(3y - 1).

(c) Solve the inequation 9t - 4 < 12t - 10.[2]

Verified working — step 1

9t - 4 < 12t - 10

The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.

Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

Have a different question?

Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.