ECZ 2012 · O-Level Paper 2 · Question 2 — Matrices
Question from ECZ 2012 · O-Level Paper 2 · Question 2
(a) Given that A = 23-15 and B = 23, find the
(a(i)) determinant of A,[1]
Verified working — step 1
A = 23-15.(a(ii)) inverse of A,[1]
Verified working — step 1
With det A = …(a(iii)) value of AB.[2]
Verified working — step 1
A is 2 × 2 and B is 2 × 1, so AB is 2 × 1.(b) Express 42x - 1 - 3x - 1 as a single fraction in its simplest form.[3]
Verified working — step 1
Common denominator (2x - 1)(x - 1).(c) Solve the inequation 4b - 3 < 6b + 4.[2]
Verified working — step 1
4b - 3 < 6b + 4The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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