ECZ 2026 · GCE Paper 2 · Question 8 — Trigonometry

Question from ECZ 2026 · GCE Paper 2 · Question 8

(a) In the triangle, AB = 125cm, BC = 57cm and angle ABC = 91.2°. Calculate

Diagram for part (a)

(a(i)) AC,[5]

Verified working — step 1

Two sides and the INCLUDED angle → cosine rule.

(a(ii)) the area of triangle ABC,[2]

Verified working — step 1

Two sides and the included angle: Area = (12)(AB)(BC) sin B.

(a(iii)) the shortest distance from B to AC.[2]

Verified working — step 1

The shortest distance from B to AC is the perpendicular height h onto AC.

(b) Solve the equation tan θ = 0.7 for 180° ≤ θ ≤ 360°.[1]

Verified working — step 1

tan-1(0.7) = 35.0°, the acute reference angle.

(c) Simplify 52x2 y25a2 b2 ÷ 13x2 y310a3 b2.[2]

Verified working — step 1

Dividing by a fraction means multiplying by its reciprocal:

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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