ECZ 2019 · GCE Paper 2 · Question 8 — Trigonometry
In triangle ABC, AC = 275km, angle BAC = 125° and angle ACB = 40°.
(a(i)) Calculate the distance BC.[4]
Verified working — step 1
Angle B = 180° - 125° - 40° = 15°.(a(ii)) Calculate the area of triangle ABC.[2]
Verified working — step 1
Area = 12× AC × BC × sin C(a(iii)) Calculate the shortest distance from A to BC.[2]
Verified working — step 1
Let h = shortest distance from A to BC.(b) Solve the equation 13 cos θ = 5 for 0° ≤ θ ≤ 360°.[2]
Verified working — step 1
13 cos θ = 5(c) Simplify 2x^2 - 18x + 3.[2]
Verified working — step 1
2x² - 18x + 3= 2x² - 9x + 3The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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