ECZ 2020 · GCE Paper 2 · Question 2 — Sequences and Series
Question from ECZ 2020 · GCE Paper 2 · Question 2
(a) Simplify y + 1y2 - 1.[2]
Verified working — step 1
y2 - 1 is a difference of two squares: (y - 1)(y + 1).(b) The sum of n terms of a geometric progression (G.P) is given by 10 - 102n. Find
(b(i)) the sum of the first 4 terms of this G.P,[2]
Verified working — step 1
The sum formula is given as Sn = 10 - 102n. Put n = 4:(b(ii)) the first term,[2]
Verified working — step 1
The first term is S1, the sum of just one term.(b(iii)) the first 4 terms.[3]
Verified working — step 1
Each term is Tn = Sn - Sn-1.The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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