ECZ 2020 · GCE Paper 2 · Question 9 — Trigonometry

Positions of a Guava (G) tree, Orange (O) tree and Lemon (L) tree on a farm: LG = 10.1m, OG = 14.2m and angle OLG = 40°.

Diagram for ECZ 2020 · GCE Paper 2 · Question 9

(a(i)) Calculate angle OGL.[5]

Verified working — step 1

Use the Sine Rule. First find angle LOG (opposite LG), using the known angle OLG (opposite OG):

(a(ii)) Calculate the area of triangle OGL.[2]

Verified working — step 1

Area = ½ × LG × OG × sin(OGL)

(a(iii)) Calculate the shortest distance from L to OG.[2]

Verified working — step 1

Let h = shortest distance from L to line OG.

(b) Solve the equation 5 cos θ = 3 for 0° ≤ θ ≤ 180°.[1]

Verified working — step 1

5cosθ = 3

(c) Simplify (99m3 n2 / 20p2 q3) ÷ (33m4 n40p2 q3).[2]

Verified working — step 1

(99m3n2/20p2q3) ÷ (33m4n40p2q3)

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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