ECZ 2020 · GCE Paper 2 · Question 9 — Trigonometry
Question from ECZ 2020 · GCE Paper 2 · Question 9
(a) The diagram below shows the positions of a Guava (G) tree, Orange (O) tree and Lemon (L) tree on a farm. Given that LG = 10.1 m, OG = 14.2 m and angle OLG = 40°; calculate
(a(i)) angle OGL,[5]
Verified working — step 1
Use the sine rule to find the angle at O first:(a(ii)) the area of triangle OGL,[2]
Verified working — step 1
Two sides and the included angle at G: Area = (12)(LG)(OG) sin(OGL)(a(iii)) the shortest distance from L to OG.[2]
Verified working — step 1
The shortest distance is the perpendicular height h from L onto OG.(b) Solve the equation 5 cos θ = 3 for 0° ≤ θ ≤ 180°.[1]
Verified working — step 1
cos θ = 35 = 0.6(c) Simplify 99m3 n220p2 q3 ÷ 33m4 n40p2 q3.[2]
Verified working — step 1
Multiply by the reciprocal:The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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