ECZ 2022 · GCE Paper 2 · Question 2 — Sequences and Series
The first three terms of a geometric progression are 3, 6 and 12 respectively.
(a) Simplify (4p3q) ÷ (p2 q6) × (pq2).[2]
Verified working — step 1
(4p3q) ÷ (p2q6) × (pq2)(b(i)) Find the nth term.[2]
Verified working — step 1
First term a = 3, common ratio r = 63= 2.(b(ii)) Find the geometric mean of 96 and 384.[2]
Verified working — step 1
Geometric mean of two numbers a and b = √(a×b)(b(iii)) Find the sum of the first 8 terms of the progression.[3]
Verified working — step 1
Sum of n terms: Sn = ar^n - 1r - 1, a=3, r=2, n=8The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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