ECZ 2011 · O-Level Paper 1 — Trigonometry
A vegetable garden is an irregular pentagon ABCDE with AB = BC = CD = AD, AE = 12 m, DE = 5 m and angles ABC, BCD and DEA all 90 degrees. Find AD.
- A. 17 m
- B. 7 m
- C. 11 m
- D. 13 m
Verified working — step 1
Triangle ADE is right-angled at E, so by Pythagoras AD2 = AE2 + DE2 = 144 + 25 = 169, giving AD = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
Have a different question?
Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.
Search any past-paper question