ECZ 2019 · GCE Paper 1 — Travel Graphs
In the same journey (rest → 10 m/sin 2 s; constant 10 m/sfor 6 s; speeding up to 24 m/sbetween 8 s and 13 s; then retarding to rest at 21 s), calculate the average speed for the whole journey.
- A. 14.5 m/s
- B. ≈ 12 m/s
- C. 24 m/s
- D. 10 m/s
Verified working — step 1
Total distance = area under the graph: first trapezium ½(6 + 8) × 10 = 70 m (2-s ramp + 6-s cruise), middle trapezium ½(10 + 24) × 5 = 85 m, final triangle ½ × 8 × 24 = 96 m. Total = 251 m over 21 s, so average speed = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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