ECZ 2025 · GCE Paper 1 — Travel Graphs

The diagram shows the speed-time graph of an object. The object starts from rest and accelerates uniformly to a speed of 20 m/sin 4 seconds, moves at this constant speed until the 10th second, then decelerates uniformly to rest after a further 5 seconds. Calculate the total distance covered during the whole journey.

Diagram for ECZ 2025 · GCE Paper 1
  • A. 300 m
  • B. 190 m
  • C. 210 m
  • D. 150 m

Verified working — step 1

The whole journey is a trapezium with parallel sides 15 (total time) and 6 (constant-speed stage, from the 4th to the 10th second) and height 20: distance = ½(15 + 6) × 20 = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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