ECZ 2025 · GCE Paper 1 — Travel Graphs
The diagram shows the speed-time graph of an object. The object starts from rest and accelerates uniformly to a speed of 20 m/sin 4 seconds, moves at this constant speed until the 10th second, then decelerates uniformly to rest after a further 5 seconds. Calculate the total distance covered during the whole journey.

- A. 300 m
- B. 190 m
- C. 210 m
- D. 150 m
Verified working — step 1
The whole journey is a trapezium with parallel sides 15 (total time) and 6 (constant-speed stage, from the 4th to the 10th second) and height 20: distance = ½(15 + 6) × 20 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
Have a different question?
Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.
Search any past-paper question