ECZ 2016 · GCE Paper 1 — Trigonometry

In the diagram, MP = 13 km, QR = 6 km and MR = 24 km. MR is parallel and equal to TQ, and PM̂R = QR̂M = 90°. T lies on MP with TQMR forming a rectangle. Find the length PQ.

Diagram for ECZ 2016 · GCE Paper 1
  • A. 25 km
  • B. 31 km
  • C. 26 km
  • D. 17 km

Verified working — step 1

TQMR is a rectangle, so TQ = MR = 24 km and MT = QR = 6 km, leaving PT = 13 − 6 = 7 km. In right triangle PTQ: PQ = √(7² + 24²) = √(49 + 576) = √625 = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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