ECZ 2023 · GCE Paper 2 · Question 6 — Vectors In Two Dimensions
In the diagram, OA = 2a, AB = b, OC = 3b, M is the midpoint of OB and OC is parallel to AB.
(a(i)) Express OB in terms of a andorb.[1]
Verified working — step 1
OB = OA + AB = …(a(ii)) Express CB in terms of a andorb.[1]
Verified working — step 1
CB = OB - OC = (2a + b) - 3b = …(a(iii)) Express AC in terms of a andorb.[1]
Verified working — step 1
AC = OC - OA = …(a(iv)) Express CM in terms of a andorb.[2]
Verified working — step 1
M is midpoint of OB, so OM = 12OB = 12(2a+b) = …(b) The equation of a curve is y = x3 - 27x. Find the coordinates of the turning points of the curve.[3]
Verified working — step 1
y = x3 - 27xThe full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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