ECZ 2010 · O-Level Paper 1 — Travel Graphs
Train A accelerates from rest to 50 m/sin 4 seconds, travels at that speed for 6 seconds, then stops in a further 2 seconds. Train B accelerates from rest to v m/sin 6 seconds then comes to rest in a further 6 seconds. Given that the trains moved the same distance, calculate v.

- A. 50
- B. 60
- C. 100
- D. 75
Verified working — step 1
Train A covers (12)(4)(50) + 6(50) + (12)(2)(50) = 100 + 300 + 50 = 450 m. Train B forms a triangle of base 12 and height v, so its distance is (12)(12)(v) = 6v. Setting 6v = 450 gives v = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
Have a different question?
Search it — if it is from a past paper or a school mock, chances are we have it worked out, or one that uses the same method.
Search any past-paper question