ECZ 2017 · O-Level Paper 1 — Travel Graphs
The speed-time graph shows a car accelerating to 30 m/sin 5 s, travelling at 30 m/suntil t = 15 s, then decelerating to rest at t = T. If the total distance travelled is 825 m, find the value of T.
- A. 30 s
- B. 40 s
- C. 45 s
- D. 55 s
Verified working — step 1
Distance is the area under the graph: triangle ½·5·30 = 75, rectangle 10·30 = 300, and falling triangle ½(T − 15)·30 = 15(T − 15). So 75 + 300 + 15(T − 15) = 150 + 15T = 825, giving T = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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