ECZ 2017 · O-Level Paper 1 — Travel Graphs

For the same journey (total distance 825 m, total time T = 45 s), find the average speed for the whole journey.

Diagram for ECZ 2017 · O-Level Paper 1
  • A. 30 m/s
  • B. 15 m/s
  • C. 20 m/s
  • D. 18⅓ m/s(≈18.3)

Verified working — step 1

Average speed = total distance ÷ total time = 825 ÷ 45 = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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