ECZ 2018 · GCE Paper 1 — Travel Graphs
The speed-time graph shows a particle which accelerated uniformly from rest to 20 m/sin 10 seconds, travelled at 20 m/sfor 20 seconds, then decelerated to rest at time t. Given that the total distance covered was 750 m, find the value of t.
- A. 50
- B. 65
- C. 45
- D. 55
Verified working — step 1
Distance = area under the graph. Acceleration phase: ½ × 10 × 20 = 100 m. Constant phase: 20 × 20 = 400 m. That leaves 750 − 500 = 250 m for the deceleration triangle: ½ × (t − 30) × 20 = 250, so t − 30 = 25 and t = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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