ECZ 2017 · GCE Paper 1 — Travel Graphs
In the same race (0 to 12 m/sover 3 s, constant 12 m/sfrom the 3rd to the 10th second, rest at 14 s), calculate the distance he covered in the first 10 seconds.
- A. 120 m
- B. 84 m
- C. 102 m
- D. 51 m
Verified working — step 1
Area for the first 10 s is a trapezium with parallel sides 7 (the constant stretch) and 10 (the whole interval) and height 12: ½(7 + 10) × 12 = 102 m. (Or triangle ½ × 3 × 12 = 18 plus rectangle 7 × 12 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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