ECZ 2021 · GCE Paper 1 — Travel Graphs
From the speed-time graph, the car decelerates from 24m/sto 18m/sin the first 3 seconds and then travels at 18m/suntil the 13th second. Calculate the distance covered in the first 13 seconds.
- A. 234 m
- B. 243 m
- C. 180 m
- D. 252 m
Verified working — step 1
Distance is the area under the graph. First 3 seconds: a trapezium of area ½(24 + 18) × 3 = 63 m. Next 10 seconds at a steady 18 m/s: 18 × 10 = 180 m. Total = 63 + 180 = …The full step-by-step working and final answer are included with Premium — checked against ECZ marking standards.
Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.
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