ECZ 2020 · O-Level Paper 1 — Travel Graphs

For the same journey (total distance 216 m over 6 s + 10 s + 4 s), calculate (c) the average speed for the whole journey.

Diagram for ECZ 2020 · O-Level Paper 1
  • A. 43.8 m/s
  • B. 18 m/s
  • C. 10.8 m/s
  • D. 12 m/s

Verified working — step 1

Average speed = total distance ÷ total time = 216 ÷ (6 + 10 + 4) = 216 ÷ 20 = …

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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