ECZ 2022 · O-Level Paper 2 · Question 8 — Graphs of Functions

Question from ECZ 2022 · O-Level Paper 2 · Question 8

(a) The variables x and y are connected by the equation y = (x - 3)(x - 5)(x + 2). Some corresponding values of x and y are shown in the table below. x-2-10123456y0243024120-60k

(a(i)) Calculate the value of k.[1]

Verified working — step 1

k is the curve's y-value at x = 6:

(a(ii)) Using a scale of 2 cm to represent 1 unit on the x axis for -2 ≤ x ≤ 6 and a scale of 2 cm to represent 10 units on the y axis for -10 ≤ y ≤ 40, draw the graph of y = (x - 3)(x - 5)(x + 2).[3]

Verified working — step 1

Plot the table's points: (-2, 0), (-1, 24), (0, 30),…

(a(iii)) Use your graph to estimate the

(a(iii)(a)) gradient of the curve at the point (-1, 24),[2]

Verified working — step 1

Draw a tangent to the curve at (-1, 24) and read its gradient from two well-spaced points.

(a(iii)(b)) area bounded by the curve, x = -1, x = 2 and y = 0.[3]

Verified working — step 1

Estimate the area between the curve and the x-axis from x = -1 to x = 2 by counting squares.

(b) Express 2x + 5 + 53x - 4 as a single fraction in its simplest form.[3]

Verified working — step 1

Common denominator (x + 5)(3x - 4):

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Original examination question © Examinations Council of Zambia. Worked solution and commentary © G12 Titan — not to be reproduced without permission.

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